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Problem of the Week; |*---The Problem of the Week---*|
Topic Started: Nov 19 2006, 07:25 AM (1,090 Views)
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(From The Art and Craft of Problem Solving by Paul Zietz)

The Forty-One Rooks
-------11/19/06-------

Forty-One Rooks are placed on a 10 X 10 chessboard. Prove that there must exist 5 rooks, none of which attack each other.
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appu_xavier
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this is impossible!
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No, it's not. Anyways, it's the Problem of the Week. It's not supposed to be easy.

Hint: The method used to prove it uses pigeons and holes. :blink:
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Stephen
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?:-( There must be a pattern like this: pigeon, hole, pigeon, hole, and to the end of that row. Then, the next row alternates the same way, but hole, pigeon, hole pigeon.... Then as you go to the next row, it switches back to the first one, and on the next row the alternate way.
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:lol: No, not literally pigeons and holes.
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Big hint: Pigeonhole Principle.
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KRK
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I have a question.

1. Can the 5 special rooks attack other rooks?
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appu_xavier
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No ,I don't think so.
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The five rooks simply don't attack any members in their group. They can attack other rooks.
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KRK
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One case. Yellow=special rooks

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Edwardted
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i dont get what their asking
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KRK
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Read the posts if you dont understand
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Edwardted
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Yea.. like Karthik's answer, if there all on the same diagnol wouldn't it work no matter what?? Or perhaps I'm confused
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theSKINzFAN
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why is it called pigeonhole....i didn't know pigeons lived in holes
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appu_xavier
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They don't
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Edwardted
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.................So why is it called a pigeon hole?

And what is a pigeon hole.
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