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| 4.999... is not 5 | |
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| Topic Started: Dec 2 2006, 02:23 AM (630 Views) | |
| Noah | Dec 2 2006, 02:23 AM Post #1 |
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Neophyte
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Mr. Williams knows about this, the whole thing where one third isn't really .333 repeating. Can somebody prove it? You cant handle the truth! |
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| appu_xavier | Dec 3 2006, 05:59 PM Post #2 |
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Poincaré Conjecture
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Do this: Multiply 4.999..... by 10. You get 49.999......... Now subtract 4.999..... from it: 49.99999... - 4.99999... 45.00000 Now that you know that 4.99999.. times 9 is 45. So do 45/9, which equals 5! So 4.99999.... does equal 5!
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| KRK | Dec 3 2006, 11:40 PM Post #3 |
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Poincaré Conjecture
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Well, basically what he said, then 45 is 9/10 of the total, so 1/10 which is the orginal 4.9999999......which turns intoi 5. |
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| Noah | Dec 4 2006, 09:16 PM Post #4 |
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Neophyte
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Yeah, i know, we did this in AHA, but I dont think its legal. For example, if you use that, it makes .3 repeating equal 1/3, but I dont think it does. |
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| KRK | Dec 5 2006, 01:50 AM Post #5 |
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Poincaré Conjecture
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I do... .33333333333333333 X 10 and subtract .333333333333333333333 to get 9/10 3.333333333333333333 -.333333333333333333333 __________________________ 3 3=9/10 1/10 is the original so we divide by 9 3/9=1/3 There ya go. |
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| Noah | Dec 5 2006, 08:28 PM Post #6 |
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Neophyte
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But if you subtract the original, you take away the mess, which cant be legal. If 9/10 is 3, then multiply .33333333333333 by 9. Its really really really close, but not it. |
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| Admin | Dec 5 2006, 08:49 PM Post #7 |
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Administrator
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No, it's exactly equal. I would explain to you why the piece you think is "missing" is equal to zero, but you haven't learned about limits yet in AHA, so just ask Mr. Williams the next time you see him. |
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| Thalia | Dec 5 2006, 09:44 PM Post #8 |
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Mathematician
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Even if you haven't learned about limits in Algebra Honors Acc., you've still learned about them last year with Mr. Williams (or Mr. Huang), in Honors Math GTC. I'm in AHA, but I still know about limits. |
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Verba vestra intellegere non possum! | |
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| Admin | Dec 5 2006, 09:45 PM Post #9 |
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Administrator
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No, By AHA I mean Advanced Honors Algebra --- Mr. William's new name for Honors Math 7. (And Noah is in AHA) |
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| theSKINzFAN | Dec 7 2006, 09:10 PM Post #10 |
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Mathematician
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what are limits again? |
| Life is something to do when you can't get to sleep. | |
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| KRK | Dec 7 2006, 10:09 PM Post #11 |
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Poincaré Conjecture
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Involving infinite, dividing that by other things-it has to be large enough |
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| appu_xavier | Dec 8 2006, 05:08 AM Post #12 |
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Poincaré Conjecture
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Karthik, I say to you: What, what? ?:-( |
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| KRK | Dec 8 2006, 11:24 AM Post #13 |
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Poincaré Conjecture
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I was reffering to the calculas Mr. Williams did last year at the end involving derivatives and limits. |
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| Edwardted | Dec 8 2006, 04:55 PM Post #14 |
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Twin Prime Conjecture
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I second this question |
| You cannot win without losing. | |
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| Admin | Dec 8 2006, 08:37 PM Post #15 |
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Administrator
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Remember the stuff you did with "lim" and that? Oh well, here is an example: The limit of 1/n as n goes to infinity is 0. |
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