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| Problem of the Week; |*---The Problem of the Week---*| 12/15 | |
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| Topic Started: Dec 16 2006, 02:56 AM (801 Views) | |
| Michel | Jan 14 2007, 03:55 PM Post #16 |
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Chipmunk
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Wait...is it sad that you agree with me, or sad that no one solved the problem? |
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You cannot shake hands with a clenched fist. -Indira Gandhi (1917 - 1984) | |
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| Myself | Jan 17 2007, 03:40 AM Post #17 |
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Smarter than the Average Amoeba
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OK, since no one is getting this, I will guess. And guess wrong I will. This is in no means a real 'proof.' Any number multiplied by two (or any even number) will have all of its digits double, therefore no odd numbers will remain in the product (except several ones.) Hey - don't make fun of me. At least I TRIED. P.S. - NEW QUESTION!! |
| muahahahahahahahaha sorry. modhax. | |
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| Michel | Jan 17 2007, 08:20 PM Post #18 |
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Chipmunk
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37 * 2 = 74. 7 is odd. Good try though. |
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You cannot shake hands with a clenched fist. -Indira Gandhi (1917 - 1984) | |
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| Myself | Jan 18 2007, 11:09 PM Post #19 |
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Smarter than the Average Amoeba
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This is the problem of the WEEK, not the problem of the month. No one is solving it, can't we get a new question? |
| muahahahahahahahaha sorry. modhax. | |
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| Michel | Jan 19 2007, 01:21 AM Post #20 |
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Chipmunk
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Admin doesn't appear to like doing that...I'll pester him tomorrow. |
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You cannot shake hands with a clenched fist. -Indira Gandhi (1917 - 1984) | |
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| Admin | Jan 19 2007, 02:02 AM Post #21 |
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Administrator
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Solve the problem and it will be changed. Good try Myself, but it's a bit more complicated than that. |
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| Michel | Jan 22 2007, 12:02 PM Post #22 |
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Chipmunk
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What if I prove that there are some? |
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You cannot shake hands with a clenched fist. -Indira Gandhi (1917 - 1984) | |
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| Admin | Jan 23 2007, 02:17 AM Post #23 |
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Administrator
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Then do so and I will consider it solved. Good luck, though, on that.... |
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| Myself | Jan 24 2007, 03:40 AM Post #24 |
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Smarter than the Average Amoeba
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Okay, I think I have it. X = persistent # (n)(X) = persistent number (n) = number Let's say we make n = 3. 3X = persistent # Now let's divide by 3. X = (persistent number)/3 Since X is a persistent number, that would mean... persistent # = (persistent #)/3 Therefore, no persistent number can be multiplied by 3. |
| muahahahahahahahaha sorry. modhax. | |
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| Admin | Jan 24 2007, 11:29 PM Post #25 |
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Administrator
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You missed the fact that the persistent numbers will be different. Obviously through the way you defined it, persistent #1 = (persistent #2)/3. |
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| 2 users reading this topic (2 Guests and 0 Anonymous) | |
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5:42 PM May 21