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Goku SSJ3 (TB28) vs Gohan (TB28)
Topic Started: Jun 28 2014, 05:23 AM (151 Views)
Posted Image SIAD

Right now it seems a fact that even SSJ2 Goku (BoG)> Base Gohan (BoG). The TB28 is the continuation of BoG. But personally I think that only Goku and Vegeta Base Base (TB28) are> = base their counterparts in BoG. For while only his SSJ multiplier on its Base in BoG state is simply huge and therefore I have this string:

   Goku SSJ3 (BoG) >>>>>>>> SSJ2 Goku (BoG)> Base Gohan (TB28) = Mystic Gohan (Boo) >>> SSJ Goku (BoG) >>>> SSJ3 Goku (TB28) >>> SSJ2 Goku >>>>> (TB28) >>>> SSJ Goku (TB28) >>>>>>>> Base Goku (TB28) >> Base Goku (BoG).

   So Gohan (TB28) remains the most powerful heroes on that point, because if Goku SSJ3 (TB28) was> = SSJ3 Goku (BoG). Goku SSJ3 (TB28) would >>> SSJ3 Goku (Bogt).

   I'm right?
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Posted Image OGEID

From what I understand SSJ3 Goku (TB28) = SSJ Goku (TB28). And as you say SSJ Goku (TB28)> = SSJ3 Goku (BoG)> = SSJ3 Goku (M13).
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Posted Image Yusuke
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I was always under the impression that Base Goku (EoZ) ~ SSJ3 Goku (Buu Saga) so no, EoZ SSJ3 Goku would probably be Super Buu level at best.
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Yusuke
Jul 11 2014, 12:49 AM
I was always under the impression that Base Goku (EoZ) ~ SSJ3 Goku (Buu Saga) so no, EoZ SSJ3 Goku would probably be Super Buu level at best.
If we think DBZ logic without BoG, Si. Although the difference between Base Gotenks (Post) and SSJ3 Goku (Boo) is huge, whether in the best Goku SSJ3 (TB28) is between SSJ2 and SSJ3 Gotenks.

   If we talk about the TB28 Goku, this has all power in SSJ, which must be equal to or greater than your SSJG. So even Goku Base (TB28) instantly destroys Gohan SSJ (TB28).
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